identify the null hypothesis,alternative hypothesis,test statistic,p-value,conclusion about the null hypothesis,and final conclusion that addresses the original claim.
According to a recent poll 52% of Americans would vote for the incumbent president.If a random sample of 250 people result in 45% who would vote for the incumbent, test the claim that the actual percentage is 52%.Use a 0.01 significance level
claim
test statistic
Critical Value
Comparison between test statistic and critical value
conclusion|||H0: proportion that would vote for the incumbent president =0.52
HA: proportion that would vote for the incumbent president %26lt; 0.52
Sample proportion phat = 0.45
Variance of proportion = p*(1-p)/n
= 0.52(0.48)/250 =0.0009984
S.D. of p is sqrt[0.000998] = 0.0316
Z = ( 0.45 - 0.52 ) / 0.0316 = -2.2154 --- test statistic
Critical value =-2.33
test statistic does not fall beyond the critical value
Conclusion: Do not reject H0;
52% of Americans would vote for the incumbent president.|||I believe the question is a difference in one bi proportion. the null is Ho: p=.5 and the alternative is H1: p%26gt;.5. Choose sig level of .01. Cr region is Reject null if z%26gt;z.05=1.645. test stat: Zcalc=x-n*Po/sq root of n*Po*Qo. Po=45% and Qo=55% osl or p value is Ho: p=.5 H1:p%26gt;.5 This should be enough info to solve
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment